Base | Representation |
---|---|
bin | 10000011111011001111… |
… | …110110000010010111111 |
3 | 11000100001222202202201202 |
4 | 100133121332300102333 |
5 | 122031330234133341 |
6 | 2224333354530115 |
7 | 144605403602024 |
oct | 20373176602277 |
9 | 4010058682652 |
10 | 1133233505471 |
11 | 3a76688525a1 |
12 | 16376573693b |
13 | 82b2c040602 |
14 | 3cbc513d54b |
15 | 1e7283e579b |
hex | 107d9fb04bf |
1133233505471 has 16 divisors (see below), whose sum is σ = 1247236320000. Its totient is φ = 1024853689728.
The previous prime is 1133233505449. The next prime is 1133233505489. The reversal of 1133233505471 is 1745053323311.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1133233505471 is a prime.
It is a super-3 number, since 3×11332335054713 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1133233505431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2380346 + ... + 2816471.
It is an arithmetic number, because the mean of its divisors is an integer number (77952270000).
Almost surely, 21133233505471 is an apocalyptic number.
1133233505471 is a deficient number, since it is larger than the sum of its proper divisors (114002814529).
1133233505471 is a wasteful number, since it uses less digits than its factorization.
1133233505471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5197358.
The product of its (nonzero) digits is 113400, while the sum is 38.
Adding to 1133233505471 its reverse (1745053323311), we get a palindrome (2878286828782).
The spelling of 1133233505471 in words is "one trillion, one hundred thirty-three billion, two hundred thirty-three million, five hundred five thousand, four hundred seventy-one".
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