Base | Representation |
---|---|
bin | 1010010011101010101101… |
… | …1100000111001101001010 |
3 | 1111010102110020220102012222 |
4 | 2210322223130013031022 |
5 | 2441134441000002310 |
6 | 40034150333134042 |
7 | 2246532206401331 |
oct | 244725334071512 |
9 | 44112406812188 |
10 | 11333000000330 |
11 | 367a33105a958 |
12 | 13304b292a322 |
13 | 64290accc478 |
14 | 2b273d328d18 |
15 | 149be6036055 |
hex | a4eab70734a |
11333000000330 has 32 divisors (see below), whose sum is σ = 20441694760704. Its totient is φ = 4523802702336.
The previous prime is 11333000000291. The next prime is 11333000000339. The reversal of 11333000000330 is 3300000033311.
11333000000330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11333000000299 and 11333000000308.
It is not an unprimeable number, because it can be changed into a prime (11333000000339) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63172739 + ... + 63351881.
It is an arithmetic number, because the mean of its divisors is an integer number (638802961272).
Almost surely, 211333000000330 is an apocalyptic number.
11333000000330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11333000000330 is a deficient number, since it is larger than the sum of its proper divisors (9108694760374).
11333000000330 is a wasteful number, since it uses less digits than its factorization.
11333000000330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192230.
The product of its (nonzero) digits is 243, while the sum is 17.
Adding to 11333000000330 its reverse (3300000033311), we get a palindrome (14633000033641).
The spelling of 11333000000330 in words is "eleven trillion, three hundred thirty-three billion, three hundred thirty", and thus it is an aban number.
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