Base | Representation |
---|---|
bin | 1010010011101010101110… |
… | …0000010110001011000101 |
3 | 1111010102110022222210200202 |
4 | 2210322223200112023011 |
5 | 2441134441241011323 |
6 | 40034150413020245 |
7 | 2246532222003206 |
oct | 244725340261305 |
9 | 44112408883622 |
10 | 11333001110213 |
11 | 367a331748812 |
12 | 13304b3184685 |
13 | 64290b2ca6c3 |
14 | 2b273d5375ad |
15 | 149be61a4d28 |
hex | a4eab8162c5 |
11333001110213 has 2 divisors, whose sum is σ = 11333001110214. Its totient is φ = 11333001110212.
The previous prime is 11333001110117. The next prime is 11333001110243. The reversal of 11333001110213 is 31201110033311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10572271759009 + 760729351204 = 3251503^2 + 872198^2 .
It is a cyclic number.
It is not a de Polignac number, because 11333001110213 - 220 = 11333000061637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11333001110243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666500555106 + 5666500555107.
It is an arithmetic number, because the mean of its divisors is an integer number (5666500555107).
Almost surely, 211333001110213 is an apocalyptic number.
It is an amenable number.
11333001110213 is a deficient number, since it is larger than the sum of its proper divisors (1).
11333001110213 is an equidigital number, since it uses as much as digits as its factorization.
11333001110213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 11333001110213 its reverse (31201110033311), we get a palindrome (42534111143524).
The spelling of 11333001110213 in words is "eleven trillion, three hundred thirty-three billion, one million, one hundred ten thousand, two hundred thirteen".
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