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1133301030131 is a prime number
BaseRepresentation
bin10000011111011110000…
…000010101110011110011
311000100020200211101011002
4100133132000111303303
5122032000030431011
62224344210112215
7144610153545644
oct20373600256363
94010220741132
101133301030131
113a76a29828a6
1216378427b66b
1382b4002352a
143cbd00b96cb
151e72e2d2c3b
hex107de015cf3

1133301030131 has 2 divisors, whose sum is σ = 1133301030132. Its totient is φ = 1133301030130.

The previous prime is 1133301030089. The next prime is 1133301030133. The reversal of 1133301030131 is 1310301033311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1133301030131 is a prime.

It is a super-2 number, since 2×11333010301312 (a number of 25 digits) contains 22 as substring.

Together with 1133301030133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1133301030133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566650515065 + 566650515066.

It is an arithmetic number, because the mean of its divisors is an integer number (566650515066).

Almost surely, 21133301030131 is an apocalyptic number.

1133301030131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133301030131 is an equidigital number, since it uses as much as digits as its factorization.

1133301030131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 1133301030131 its reverse (1310301033311), we get a palindrome (2443602063442).

The spelling of 1133301030131 in words is "one trillion, one hundred thirty-three billion, three hundred one million, thirty thousand, one hundred thirty-one".