Base | Representation |
---|---|
bin | 1010010011101010110000… |
… | …1010010011101101011011 |
3 | 1111010102111002200122210121 |
4 | 2210322230022103231123 |
5 | 2441140002100011141 |
6 | 40034151444454111 |
7 | 2246532414336103 |
oct | 244725412235533 |
9 | 44112432618717 |
10 | 11333012110171 |
11 | 367a337981194 |
12 | 13304b69aa337 |
13 | 64291067c45b |
14 | 2b2740b9c203 |
15 | 149be71291d1 |
hex | a4eac293b5b |
11333012110171 has 2 divisors, whose sum is σ = 11333012110172. Its totient is φ = 11333012110170.
The previous prime is 11333012110051. The next prime is 11333012110219. The reversal of 11333012110171 is 17101121033311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11333012110171 - 211 = 11333012108123 is a prime.
It is not a weakly prime, because it can be changed into another prime (11333015110171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666506055085 + 5666506055086.
It is an arithmetic number, because the mean of its divisors is an integer number (5666506055086).
Almost surely, 211333012110171 is an apocalyptic number.
11333012110171 is a deficient number, since it is larger than the sum of its proper divisors (1).
11333012110171 is an equidigital number, since it uses as much as digits as its factorization.
11333012110171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 378, while the sum is 25.
Adding to 11333012110171 its reverse (17101121033311), we get a palindrome (28434133143482).
The spelling of 11333012110171 in words is "eleven trillion, three hundred thirty-three billion, twelve million, one hundred ten thousand, one hundred seventy-one".
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