11333013222021 has 4 divisors (see below), whose sum is σ = 15110684296032. Its totient is φ = 7555342148012.

The previous prime is 11333013222019. The next prime is 11333013222031. The reversal of 11333013222021 is 12022231033311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11333013222021 - 2¹ = 11333013222019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11333013221982 and 11333013222000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11333013222031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1888835537001 + ... + 1888835537006.

It is an arithmetic number, because the mean of its divisors is an integer number (3777671074008).

Almost surely, 2^{11333013222021} is an apocalyptic number.

It is an amenable number.

11333013222021 is a deficient number, since it is larger than the sum of its proper divisors (3777671074011).

11333013222021 is an equidigital number, since it uses as much as digits as its factorization.

11333013222021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3777671074010.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 11333013222021 its reverse (12022231033311), we get a palindrome (23355244255332).

The spelling of 11333013222021 in words is "eleven trillion, three hundred thirty-three billion, thirteen million, two hundred twenty-two thousand, twenty-one".