Base | Representation |
---|---|
bin | 110100110001100000… |
… | …0011101100011010111 |
3 | 101211112011210102201002 |
4 | 1221203000131203113 |
5 | 3324100013341002 |
6 | 124021351453515 |
7 | 11121266635313 |
oct | 1514300354327 |
9 | 354464712632 |
10 | 113330215127 |
11 | 44076a52018 |
12 | 19b6a08729b |
13 | a8c142b0bc |
14 | 56b15c6b43 |
15 | 2e34668002 |
hex | 1a6301d8d7 |
113330215127 has 2 divisors, whose sum is σ = 113330215128. Its totient is φ = 113330215126.
The previous prime is 113330215087. The next prime is 113330215139. The reversal of 113330215127 is 721512033311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113330215127 - 216 = 113330149591 is a prime.
It is a super-2 number, since 2×1133302151272 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 113330215127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113330215627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56665107563 + 56665107564.
It is an arithmetic number, because the mean of its divisors is an integer number (56665107564).
Almost surely, 2113330215127 is an apocalyptic number.
113330215127 is a deficient number, since it is larger than the sum of its proper divisors (1).
113330215127 is an equidigital number, since it uses as much as digits as its factorization.
113330215127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780, while the sum is 29.
Adding to 113330215127 its reverse (721512033311), we get a palindrome (834842248438).
The spelling of 113330215127 in words is "one hundred thirteen billion, three hundred thirty million, two hundred fifteen thousand, one hundred twenty-seven".
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