11333202313133 has 4 divisors (see below), whose sum is σ = 11609621881788. Its totient is φ = 11056782744480.

The previous prime is 11333202313067. The next prime is 11333202313247. The reversal of 11333202313133 is 33131320233311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3284786510404 + 8048415802729 = 1812398^2 + 2836973^2 .

It is a cyclic number.

It is not a de Polignac number, because 11333202313133 - 2²⁶ = 11333135204269 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11333202313096 and 11333202313105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11333202313633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138209784266 + ... + 138209784347.

It is an arithmetic number, because the mean of its divisors is an integer number (2902405470447).

Almost surely, 2^{11333202313133} is an apocalyptic number.

It is an amenable number.

11333202313133 is a deficient number, since it is larger than the sum of its proper divisors (276419568655).

11333202313133 is an equidigital number, since it uses as much as digits as its factorization.

11333202313133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 276419568654.

The product of its (nonzero) digits is 8748, while the sum is 29.

Adding to 11333202313133 its reverse (33131320233311), we get a palindrome (44464522546444).

The spelling of 11333202313133 in words is "eleven trillion, three hundred thirty-three billion, two hundred two million, three hundred thirteen thousand, one hundred thirty-three".