Base | Representation |
---|---|
bin | 11001110001001100110111… |
… | …010100101001111100001111 |
3 | 112212021110021222112221110021 |
4 | 121301030313110221330033 |
5 | 104323313401412413403 |
6 | 1041012035141323011 |
7 | 32604661213061224 |
oct | 3161146724517417 |
9 | 485243258487407 |
10 | 113332230201103 |
11 | 33124a24424301 |
12 | 10864666706467 |
13 | 4b3125006c074 |
14 | 1ddb44868394b |
15 | d18070e248bd |
hex | 671337529f0f |
113332230201103 has 2 divisors, whose sum is σ = 113332230201104. Its totient is φ = 113332230201102.
The previous prime is 113332230201097. The next prime is 113332230201131. The reversal of 113332230201103 is 301102032233311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113332230201103 - 245 = 78147858112271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113332230201403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56666115100551 + 56666115100552.
It is an arithmetic number, because the mean of its divisors is an integer number (56666115100552).
Almost surely, 2113332230201103 is an apocalyptic number.
113332230201103 is a deficient number, since it is larger than the sum of its proper divisors (1).
113332230201103 is an equidigital number, since it uses as much as digits as its factorization.
113332230201103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 113332230201103 its reverse (301102032233311), we get a palindrome (414434262434414).
The spelling of 113332230201103 in words is "one hundred thirteen trillion, three hundred thirty-two billion, two hundred thirty million, two hundred one thousand, one hundred three".
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