Base | Representation |
---|---|
bin | 10101000111000001… |
… | …10110010110101001 |
3 | 1002020211110211122212 |
4 | 22203200312112221 |
5 | 141202301411131 |
6 | 5112330254505 |
7 | 550563611555 |
oct | 124340662651 |
9 | 32224424585 |
10 | 11333232041 |
11 | 489634aa7a |
12 | 2243587435 |
13 | 10b7c8c581 |
14 | 797254865 |
15 | 464e64a2b |
hex | 2a38365a9 |
11333232041 has 2 divisors, whose sum is σ = 11333232042. Its totient is φ = 11333232040.
The previous prime is 11333232023. The next prime is 11333232133. The reversal of 11333232041 is 14023233311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9964232041 + 1369000000 = 99821^2 + 37000^2 .
It is an emirp because it is prime and its reverse (14023233311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11333232041 - 226 = 11266123177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11333231998 and 11333232016.
It is not a weakly prime, because it can be changed into another prime (11333232541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666616020 + 5666616021.
It is an arithmetic number, because the mean of its divisors is an integer number (5666616021).
Almost surely, 211333232041 is an apocalyptic number.
It is an amenable number.
11333232041 is a deficient number, since it is larger than the sum of its proper divisors (1).
11333232041 is an equidigital number, since it uses as much as digits as its factorization.
11333232041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11333232041 its reverse (14023233311), we get a palindrome (25356465352).
The spelling of 11333232041 in words is "eleven billion, three hundred thirty-three million, two hundred thirty-two thousand, forty-one".
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