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11333243401 is a prime number
BaseRepresentation
bin10101000111000001…
…11001001000001001
31002020211111102020121
422203200321020021
5141202302242101
65112330423241
7550563656644
oct124340711011
932224442217
1011333243401
114896358567
122243591b21
1310b7c947ac
14797258a5b
15464e680a1
hex2a3839209

11333243401 has 2 divisors, whose sum is σ = 11333243402. Its totient is φ = 11333243400.

The previous prime is 11333243381. The next prime is 11333243459. The reversal of 11333243401 is 10434233311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8149575625 + 3183667776 = 90275^2 + 56424^2 .

It is an emirp because it is prime and its reverse (10434233311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11333243401 - 29 = 11333242889 is a prime.

It is not a weakly prime, because it can be changed into another prime (11333243501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666621700 + 5666621701.

It is an arithmetic number, because the mean of its divisors is an integer number (5666621701).

Almost surely, 211333243401 is an apocalyptic number.

It is an amenable number.

11333243401 is a deficient number, since it is larger than the sum of its proper divisors (1).

11333243401 is an equidigital number, since it uses as much as digits as its factorization.

11333243401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11333243401 its reverse (10434233311), we get a palindrome (21767476712).

The spelling of 11333243401 in words is "eleven billion, three hundred thirty-three million, two hundred forty-three thousand, four hundred one".