Base | Representation |
---|---|
bin | 10101000111001001… |
… | …00101101001100001 |
3 | 1002020220022122011210 |
4 | 22203210211221201 |
5 | 141203024242233 |
6 | 5112403300333 |
7 | 550605133263 |
oct | 124344455141 |
9 | 32226278153 |
10 | 11334212193 |
11 | 489695a417 |
12 | 224397a6a9 |
13 | 10b8243745 |
14 | 79742bb33 |
15 | 4650aa163 |
hex | 2a3925a61 |
11334212193 has 4 divisors (see below), whose sum is σ = 15112282928. Its totient is φ = 7556141460.
The previous prime is 11334212191. The next prime is 11334212203. The reversal of 11334212193 is 39121243311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 39121243311 = 3 ⋅13040414437.
It is not a de Polignac number, because 11334212193 - 21 = 11334212191 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11334212193.
It is not an unprimeable number, because it can be changed into a prime (11334212191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1889035363 + ... + 1889035368.
It is an arithmetic number, because the mean of its divisors is an integer number (3778070732).
Almost surely, 211334212193 is an apocalyptic number.
It is an amenable number.
11334212193 is a deficient number, since it is larger than the sum of its proper divisors (3778070735).
11334212193 is an equidigital number, since it uses as much as digits as its factorization.
11334212193 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3778070734.
The product of its digits is 3888, while the sum is 30.
The spelling of 11334212193 in words is "eleven billion, three hundred thirty-four million, two hundred twelve thousand, one hundred ninety-three".
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