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113344010131 = 1114449713129
BaseRepresentation
bin110100110001111010…
…1000101011110010011
3101211120010202021220011
41221203311011132103
53324112031311011
6124023003255351
711121525122062
oct1514365053623
9354503667804
10113344010131
1144083814450
1219b7281a557
13a8c424b121
1456b33781d9
152e35990621
hex1a63d45793

113344010131 has 8 divisors (see below), whose sum is σ = 123656742000. Its totient is φ = 103032733440.

The previous prime is 113344010119. The next prime is 113344010141. The reversal of 113344010131 is 131010443311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113344010131 - 25 = 113344010099 is a prime.

It is a super-2 number, since 2×1133440101312 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (113344010141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 197626 + ... + 515503.

It is an arithmetic number, because the mean of its divisors is an integer number (15457092750).

Almost surely, 2113344010131 is an apocalyptic number.

113344010131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

113344010131 is a deficient number, since it is larger than the sum of its proper divisors (10312731869).

113344010131 is a wasteful number, since it uses less digits than its factorization.

113344010131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 727589.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 113344010131 its reverse (131010443311), we get a palindrome (244354453442).

The spelling of 113344010131 in words is "one hundred thirteen billion, three hundred forty-four million, ten thousand, one hundred thirty-one".

Divisors: 1 11 14449 158939 713129 7844419 10304000921 113344010131