Base | Representation |
---|---|
bin | 110100110001111010… |
… | …1000101101110000110 |
3 | 101211120010202100021121 |
4 | 1221203311011232012 |
5 | 3324112031324032 |
6 | 124023003304154 |
7 | 11121525125035 |
oct | 1514365055606 |
9 | 354503670247 |
10 | 113344011142 |
11 | 4408381518a |
12 | 19b7281b05a |
13 | a8c424b71b |
14 | 56b337871c |
15 | 2e35990a97 |
hex | 1a63d45b86 |
113344011142 has 4 divisors (see below), whose sum is σ = 170016016716. Its totient is φ = 56672005570.
The previous prime is 113344011127. The next prime is 113344011167. The reversal of 113344011142 is 241110443311.
It is a semiprime because it is the product of two primes.
It is a super-4 number, since 4×1133440111424 (a number of 45 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28336002784 + ... + 28336002787.
It is an arithmetic number, because the mean of its divisors is an integer number (42504004179).
Almost surely, 2113344011142 is an apocalyptic number.
113344011142 is a deficient number, since it is larger than the sum of its proper divisors (56672005574).
113344011142 is an equidigital number, since it uses as much as digits as its factorization.
113344011142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56672005573.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 113344011142 its reverse (241110443311), we get a palindrome (354454454453).
The spelling of 113344011142 in words is "one hundred thirteen billion, three hundred forty-four million, eleven thousand, one hundred forty-two".
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