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1133441431013 = 2339484583767
BaseRepresentation
bin10000011111100110010…
…111111011010111100101
311000100121111000110221202
4100133212113323113211
5122032242001243023
62224410143252245
7144613510125653
oct20374627732745
94010544013852
101133441431013
113a7765159091
121638032aa085
1382b63141188
143cc049c5dd3
151e73b7b8128
hex107e65fb5e5

1133441431013 has 4 divisors (see below), whose sum is σ = 1133926017120. Its totient is φ = 1132956844908.

The previous prime is 1133441430977. The next prime is 1133441431043. The reversal of 1133441431013 is 3101341443311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1133441431013 - 222 = 1133437236709 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133441431043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242289545 + ... + 242294222.

It is an arithmetic number, because the mean of its divisors is an integer number (283481504280).

Almost surely, 21133441431013 is an apocalyptic number.

It is an amenable number.

1133441431013 is a deficient number, since it is larger than the sum of its proper divisors (484586107).

1133441431013 is an equidigital number, since it uses as much as digits as its factorization.

1133441431013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 484586106.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1133441431013 its reverse (3101341443311), we get a palindrome (4234782874324).

The spelling of 1133441431013 in words is "one trillion, one hundred thirty-three billion, four hundred forty-one million, four hundred thirty-one thousand, thirteen".

Divisors: 1 2339 484583767 1133441431013