1133442133 has 4 divisors (see below), whose sum is σ = 1133517868. Its totient is φ = 1133366400.

The previous prime is 1133442113. The next prime is 1133442143. The reversal of 1133442133 is 3312443311.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3312443311 = 607 ⋅5457073.

It can be written as a sum of positive squares in 2 ways, for example, as 335549124 + 797893009 = 18318^2 + 28247^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1133442133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1133442098 and 1133442107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133442103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7068 + ... + 48133.

It is an arithmetic number, because the mean of its divisors is an integer number (283379467).

Almost surely, 2^1133442133 is an apocalyptic number.

It is an amenable number.

1133442133 is a deficient number, since it is larger than the sum of its proper divisors (75735).

1133442133 is an equidigital number, since it uses as much as digits as its factorization.

1133442133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75734.

The product of its digits is 2592, while the sum is 25.

The square root of 1133442133 is about 33666.6323382663. The cubic root of 1133442133 is about 1042.6369636043.

Adding to 1133442133 its reverse (3312443311), we get a palindrome (4445885444).

The spelling of 1133442133 in words is "one billion, one hundred thirty-three million, four hundred forty-two thousand, one hundred thirty-three".