Base | Representation |
---|---|
bin | 1010010011110000010011… |
… | …1111010111011110111111 |
3 | 1111010120022221221221200202 |
4 | 2210330010333113132333 |
5 | 2441201030104224041 |
6 | 40034555403114115 |
7 | 2246614351612031 |
oct | 244740477273677 |
9 | 44116287857622 |
10 | 11334502414271 |
11 | 367aa32139773 |
12 | 1330851b1293b |
13 | 642aba3583ba |
14 | 2b2842a99c51 |
15 | 149c82daaa9b |
hex | a4f04fd77bf |
11334502414271 has 2 divisors, whose sum is σ = 11334502414272. Its totient is φ = 11334502414270.
The previous prime is 11334502414259. The next prime is 11334502414427. The reversal of 11334502414271 is 17241420543311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11334502414271 is a prime.
It is a super-2 number, since 2×113345024142712 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11334502414871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5667251207135 + 5667251207136.
It is an arithmetic number, because the mean of its divisors is an integer number (5667251207136).
Almost surely, 211334502414271 is an apocalyptic number.
11334502414271 is a deficient number, since it is larger than the sum of its proper divisors (1).
11334502414271 is an equidigital number, since it uses as much as digits as its factorization.
11334502414271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 38.
Adding to 11334502414271 its reverse (17241420543311), we get a palindrome (28575922957582).
The spelling of 11334502414271 in words is "eleven trillion, three hundred thirty-four billion, five hundred two million, four hundred fourteen thousand, two hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •