Base | Representation |
---|---|
bin | 11001110001011001000100… |
… | …111111010111010001110001 |
3 | 112212022201010221020101211210 |
4 | 121301121010333113101301 |
5 | 104324022231131340140 |
6 | 1041022044332230333 |
7 | 32605634203666533 |
oct | 3161310477272161 |
9 | 485281127211753 |
10 | 113345344402545 |
11 | 3312a54400aa12 |
12 | 1086710660b3a9 |
13 | 4b3255ccb7588 |
14 | 1ddbd30259853 |
15 | d1858c3d3d80 |
hex | 671644fd7471 |
113345344402545 has 16 divisors (see below), whose sum is σ = 181388540954880. Its totient is φ = 60438853711104.
The previous prime is 113345344402531. The next prime is 113345344402639. The reversal of 113345344402545 is 545204443543311.
It is a happy number.
It is not a de Polignac number, because 113345344402545 - 29 = 113345344402033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113345344402494 and 113345344402503.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 749711704 + ... + 749862873.
It is an arithmetic number, because the mean of its divisors is an integer number (11336783809680).
Almost surely, 2113345344402545 is an apocalyptic number.
113345344402545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
113345344402545 is a deficient number, since it is larger than the sum of its proper divisors (68043196552335).
113345344402545 is a wasteful number, since it uses less digits than its factorization.
113345344402545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1499579624.
The product of its (nonzero) digits is 6912000, while the sum is 48.
Adding to 113345344402545 its reverse (545204443543311), we get a palindrome (658549787945856).
The spelling of 113345344402545 in words is "one hundred thirteen trillion, three hundred forty-five billion, three hundred forty-four million, four hundred two thousand, five hundred forty-five".
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