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113352305403 = 337784101801
BaseRepresentation
bin110100110010001010…
…0101110101011111011
3101211120201100201212110
41221210110232223323
53324121142233103
6124023501143403
711121655461411
oct1514424565373
9354521321773
10113352305403
114408846a847
1219b7555ab63
13a8c5b93a7c
1456b44d72b1
152e3657d403
hex1a6452eafb

113352305403 has 4 divisors (see below), whose sum is σ = 151136407208. Its totient is φ = 75568203600.

The previous prime is 113352305399. The next prime is 113352305419. The reversal of 113352305403 is 304503253311.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 113352305403 - 22 = 113352305399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113352305453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18892050898 + ... + 18892050903.

It is an arithmetic number, because the mean of its divisors is an integer number (37784101802).

Almost surely, 2113352305403 is an apocalyptic number.

113352305403 is a deficient number, since it is larger than the sum of its proper divisors (37784101805).

113352305403 is an equidigital number, since it uses as much as digits as its factorization.

113352305403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37784101804.

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 113352305403 its reverse (304503253311), we get a palindrome (417855558714).

The spelling of 113352305403 in words is "one hundred thirteen billion, three hundred fifty-two million, three hundred five thousand, four hundred three".

Divisors: 1 3 37784101801 113352305403