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11335245433373 is a prime number
BaseRepresentation
bin1010010011110011000101…
…0001110000101000011101
31111010122020202002020021202
42210330301101300220131
52441204040312331443
640035201224405245
72246641643304341
oct244746121605035
944118222066252
1011335245433373
1136802835a0a44
121330a1a916825
13642ba827a584
142b28b3631621
15149cc82297b8
hexa4f31470a1d

11335245433373 has 2 divisors, whose sum is σ = 11335245433374. Its totient is φ = 11335245433372.

The previous prime is 11335245433349. The next prime is 11335245433381. The reversal of 11335245433373 is 37333454253311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11139560409604 + 195685023769 = 3337598^2 + 442363^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11335245433373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11335245433273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5667622716686 + 5667622716687.

It is an arithmetic number, because the mean of its divisors is an integer number (5667622716687).

Almost surely, 211335245433373 is an apocalyptic number.

It is an amenable number.

11335245433373 is a deficient number, since it is larger than the sum of its proper divisors (1).

11335245433373 is an equidigital number, since it uses as much as digits as its factorization.

11335245433373 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4082400, while the sum is 47.

Adding to 11335245433373 its reverse (37333454253311), we get a palindrome (48668699686684).

The spelling of 11335245433373 in words is "eleven trillion, three hundred thirty-five billion, two hundred forty-five million, four hundred thirty-three thousand, three hundred seventy-three".