113355511433 has 4 divisors (see below), whose sum is σ = 113356229700. Its totient is φ = 113354793168.

The previous prime is 113355511397. The next prime is 113355511457. The reversal of 113355511433 is 334115553311.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 23904870544 + 89450640889 = 154612^2 + 299083^2 .

It is a cyclic number.

It is not a de Polignac number, because 113355511433 - 2⁸ = 113355511177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113355511393 and 113355511402.

It is not an unprimeable number, because it can be changed into a prime (113355511933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7910 + ... + 476207.

It is an arithmetic number, because the mean of its divisors is an integer number (28339057425).

Almost surely, 2^113355511433 is an apocalyptic number.

It is an amenable number.

113355511433 is a deficient number, since it is larger than the sum of its proper divisors (718267).

113355511433 is an equidigital number, since it uses as much as digits as its factorization.

113355511433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 718266.

The product of its digits is 40500, while the sum is 35.

The spelling of 113355511433 in words is "one hundred thirteen billion, three hundred fifty-five million, five hundred eleven thousand, four hundred thirty-three".