Base | Representation |
---|---|
bin | 11001110001101010100001… |
… | …101111001010100101000100 |
3 | 112212101111111200010221022111 |
4 | 121301222201233022211010 |
5 | 104324324114024302000 |
6 | 1041034423423510404 |
7 | 32610166406361322 |
oct | 3161524157124504 |
9 | 485344450127274 |
10 | 113364080306500 |
11 | 33137488a34961 |
12 | 1086a875158404 |
13 | 4b3425781858a |
14 | 1ddcbca6c8d12 |
15 | d18cd71a2cba |
hex | 671aa1bca944 |
113364080306500 has 48 divisors (see below), whose sum is σ = 247623129726336. Its totient is φ = 45339042684000.
The previous prime is 113364080306461. The next prime is 113364080306507. The reversal of 113364080306500 is 5603080463311.
It is a super-2 number, since 2×1133640803065002 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (113364080306507) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13028656 + ... + 19911655.
It is an arithmetic number, because the mean of its divisors is an integer number (5158815202632).
Almost surely, 2113364080306500 is an apocalyptic number.
113364080306500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113364080306500 is an abundant number, since it is smaller than the sum of its proper divisors (134259049419836).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113364080306500 is a wasteful number, since it uses less digits than its factorization.
113364080306500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32947213 (or 32947201 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 113364080306500 in words is "one hundred thirteen trillion, three hundred sixty-four billion, eighty million, three hundred six thousand, five hundred".
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