Base | Representation |
---|---|
bin | 110100110011011001… |
… | …1111111000001011101 |
3 | 101211200121220202002122 |
4 | 1221212303333001131 |
5 | 3324212334200323 |
6 | 124031552032325 |
7 | 11123003356220 |
oct | 1514663770135 |
9 | 354617822078 |
10 | 113394053213 |
11 | 440a9a94571 |
12 | 19b875326a5 |
13 | a90172000c |
14 | 56b9c835b7 |
15 | 2e3a077ec8 |
hex | 1a66cff05d |
113394053213 has 4 divisors (see below), whose sum is σ = 129593203680. Its totient is φ = 97194902748.
The previous prime is 113394053183. The next prime is 113394053231. The reversal of 113394053213 is 312350493311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 113394053213 - 216 = 113393987677 is a prime.
It is a super-2 number, since 2×1133940532132 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113394053413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8099575223 + ... + 8099575236.
It is an arithmetic number, because the mean of its divisors is an integer number (32398300920).
Almost surely, 2113394053213 is an apocalyptic number.
It is an amenable number.
113394053213 is a deficient number, since it is larger than the sum of its proper divisors (16199150467).
113394053213 is an equidigital number, since it uses as much as digits as its factorization.
113394053213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16199150466.
The product of its (nonzero) digits is 29160, while the sum is 35.
The spelling of 113394053213 in words is "one hundred thirteen billion, three hundred ninety-four million, fifty-three thousand, two hundred thirteen".
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