1133986014000 has 2560 divisors, whose sum is σ = 5134299955200. Its totient is φ = 233694720000.

The previous prime is 1133986013989. The next prime is 1133986014041. The reversal of 1133986014000 is 4106893311.

1133986014000 is a `hidden beast` number, since 1 + 1 + 3 + 3 + 9 + 8 + 601 + 40 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is an unprimeable number.

It is a polite number, since it can be written in 511 ways as a sum of consecutive naturals, for example, 15971633965 + ... + 15971634035.

It is an arithmetic number, because the mean of its divisors is an integer number (2005585920).

Almost surely, 2^{1133986014000} is an apocalyptic number.

1133986014000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1133986014000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2567149977600).

1133986014000 is an abundant number, since it is smaller than the sum of its proper divisors (4000313941200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1133986014000 is a wasteful number, since it uses less digits than its factorization.

1133986014000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 217 (or 195 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 36.

The spelling of 1133986014000 in words is "one trillion, one hundred thirty-three billion, nine hundred eighty-six million, fourteen thousand".