Base | Representation |
---|---|
bin | 10101000111110101… |
… | …01010101100101001 |
3 | 1002021022012200121112 |
4 | 22203322222230221 |
5 | 141211020000131 |
6 | 5113131320105 |
7 | 551005260416 |
oct | 124372525451 |
9 | 32238180545 |
10 | 11340000041 |
11 | 489a152967 |
12 | 22458b0035 |
13 | 10b94bbcc6 |
14 | 7980d710d |
15 | 46585002b |
hex | 2a3eaab29 |
11340000041 has 4 divisors (see below), whose sum is σ = 11340215952. Its totient is φ = 11339784132.
The previous prime is 11340000037. The next prime is 11340000097. The reversal of 11340000041 is 14000004311.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14000004311 = 163 ⋅85889597.
It is a cyclic number.
It is not a de Polignac number, because 11340000041 - 22 = 11340000037 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11339999980 and 11340000025.
It is not an unprimeable number, because it can be changed into a prime (11340000031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27386 + ... + 153068.
It is an arithmetic number, because the mean of its divisors is an integer number (2835053988).
Almost surely, 211340000041 is an apocalyptic number.
It is an amenable number.
11340000041 is a deficient number, since it is larger than the sum of its proper divisors (215911).
11340000041 is an equidigital number, since it uses as much as digits as its factorization.
11340000041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 215910.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 11340000041 its reverse (14000004311), we get a palindrome (25340004352).
The spelling of 11340000041 in words is "eleven billion, three hundred forty million, forty-one", and thus it is an aban number.
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