1134003433 has 2 divisors, whose sum is σ = 1134003434. Its totient is φ = 1134003432.

The previous prime is 1134003421. The next prime is 1134003463. The reversal of 1134003433 is 3343004311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1113690384 + 20313049 = 33372^2 + 4507^2 .

It is an emirp because it is prime and its reverse (3343004311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1134003433 - 2¹³ = 1133995241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1134003413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567001716 + 567001717.

It is an arithmetic number, because the mean of its divisors is an integer number (567001717).

Almost surely, 2^1134003433 is an apocalyptic number.

It is an amenable number.

1134003433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134003433 is an equidigital number, since it uses as much as digits as its factorization.

1134003433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 22.

The square root of 1134003433 is about 33674.9674535849. The cubic root of 1134003433 is about 1042.8090457752.

Adding to 1134003433 its reverse (3343004311), we get a palindrome (4477007744).

The spelling of 1134003433 in words is "one billion, one hundred thirty-four million, three thousand, four hundred thirty-three".