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1134014173433 is a prime number
BaseRepresentation
bin10000100000001000100…
…000110001000011111001
311000102002101201210211222
4100200020200301003321
5122034430112022213
62224543043201425
7144633633300641
oct20401040610371
94012071653758
101134014173433
113a7a29489a29
12163943076275
1382c249b510b
143cc5aab5521
151e771bee808
hex108088310f9

1134014173433 has 2 divisors, whose sum is σ = 1134014173434. Its totient is φ = 1134014173432.

The previous prime is 1134014173427. The next prime is 1134014173447. The reversal of 1134014173433 is 3343714104311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1077915303529 + 56098869904 = 1038227^2 + 236852^2 .

It is a cyclic number.

It is not a de Polignac number, because 1134014173433 - 24 = 1134014173417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1134014173393 and 1134014173402.

It is not a weakly prime, because it can be changed into another prime (1134014170433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567007086716 + 567007086717.

It is an arithmetic number, because the mean of its divisors is an integer number (567007086717).

Almost surely, 21134014173433 is an apocalyptic number.

It is an amenable number.

1134014173433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134014173433 is an equidigital number, since it uses as much as digits as its factorization.

1134014173433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36288, while the sum is 35.

Adding to 1134014173433 its reverse (3343714104311), we get a palindrome (4477728277744).

The spelling of 1134014173433 in words is "one trillion, one hundred thirty-four billion, fourteen million, one hundred seventy-three thousand, four hundred thirty-three".