Base | Representation |
---|---|
bin | 1010010100000101100010… |
… | …0111101010110010110111 |
3 | 1111011010001001211102121021 |
4 | 2211001120213222302313 |
5 | 2441244212304032401 |
6 | 40041341032002011 |
7 | 2250205511301505 |
oct | 245013047526267 |
9 | 44133031742537 |
10 | 11340200455351 |
11 | 3682396578329 |
12 | 1331982230307 |
13 | 6434b79bb841 |
14 | 2b2c23745675 |
15 | 149eb82492a1 |
hex | a50589eacb7 |
11340200455351 has 2 divisors, whose sum is σ = 11340200455352. Its totient is φ = 11340200455350.
The previous prime is 11340200455333. The next prime is 11340200455387. The reversal of 11340200455351 is 15355400204311.
11340200455351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11340200455351 - 231 = 11338052971703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11340200455301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670100227675 + 5670100227676.
It is an arithmetic number, because the mean of its divisors is an integer number (5670100227676).
Almost surely, 211340200455351 is an apocalyptic number.
11340200455351 is a deficient number, since it is larger than the sum of its proper divisors (1).
11340200455351 is an equidigital number, since it uses as much as digits as its factorization.
11340200455351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 11340200455351 its reverse (15355400204311), we get a palindrome (26695600659662).
The spelling of 11340200455351 in words is "eleven trillion, three hundred forty billion, two hundred million, four hundred fifty-five thousand, three hundred fifty-one".
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