Base | Representation |
---|---|
bin | 11001110010001101110111… |
… | …000111101111000111101011 |
3 | 112212112010102202102201220011 |
4 | 121302031313013233013223 |
5 | 104330434314112024003 |
6 | 1041104100243512351 |
7 | 32613011525624002 |
oct | 3162156707570753 |
9 | 485463382381804 |
10 | 113402020033003 |
11 | 33151587a18a29 |
12 | 108760a30886b7 |
13 | 4b379c2aac1a0 |
14 | 20009893cbc39 |
15 | d19ca7d6d46d |
hex | 6723771ef1eb |
113402020033003 has 4 divisors (see below), whose sum is σ = 122125252343248. Its totient is φ = 104678787722760.
The previous prime is 113402020032997. The next prime is 113402020033063. The reversal of 113402020033003 is 300330020204311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113402020033003 - 217 = 113402019901931 is a prime.
It is a super-2 number, since 2×1134020200330032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113402020033063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4361616155103 + ... + 4361616155128.
It is an arithmetic number, because the mean of its divisors is an integer number (30531313085812).
Almost surely, 2113402020033003 is an apocalyptic number.
113402020033003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
113402020033003 is a deficient number, since it is larger than the sum of its proper divisors (8723232310245).
113402020033003 is an equidigital number, since it uses as much as digits as its factorization.
113402020033003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8723232310244.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 113402020033003 its reverse (300330020204311), we get a palindrome (413732040237314).
The spelling of 113402020033003 in words is "one hundred thirteen trillion, four hundred two billion, twenty million, thirty-three thousand, three".
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