11341101113 has 2 divisors, whose sum is σ = 11341101114. Its totient is φ = 11341101112.

The previous prime is 11341101097. The next prime is 11341101133. The reversal of 11341101113 is 31110114311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7696201984 + 3644899129 = 87728^2 + 60373^2 .

It is a cyclic number.

It is not a de Polignac number, because 11341101113 - 2⁴ = 11341101097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11341101091 and 11341101100.

It is not a weakly prime, because it can be changed into another prime (11341101133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670550556 + 5670550557.

It is an arithmetic number, because the mean of its divisors is an integer number (5670550557).

Almost surely, 2^11341101113 is an apocalyptic number.

It is an amenable number.

11341101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11341101113 is an equidigital number, since it uses as much as digits as its factorization.

11341101113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 11341101113 its reverse (31110114311), we get a palindrome (42451215424).

The spelling of 11341101113 in words is "eleven billion, three hundred forty-one million, one hundred one thousand, one hundred thirteen".