113411341441331 has 4 divisors (see below), whose sum is σ = 113480621431632. Its totient is φ = 113342061451032.

The previous prime is 113411341441327. The next prime is 113411341441367. The reversal of 113411341441331 is 133144143114311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113411341441331 - 2² = 113411341441327 is a prime.

It is a super-2 number, since 2×113411341441331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113411341441291 and 113411341441300.

It is not an unprimeable number, because it can be changed into a prime (113411341441031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34639992695 + ... + 34639995968.

It is an arithmetic number, because the mean of its divisors is an integer number (28370155357908).

Almost surely, 2^{113411341441331} is an apocalyptic number.

113411341441331 is a deficient number, since it is larger than the sum of its proper divisors (69279990301).

113411341441331 is an equidigital number, since it uses as much as digits as its factorization.

113411341441331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69279990300.

The product of its digits is 20736, while the sum is 35.

Adding to 113411341441331 its reverse (133144143114311), we get a palindrome (246555484555642).

The spelling of 113411341441331 in words is "one hundred thirteen trillion, four hundred eleven billion, three hundred forty-one million, four hundred forty-one thousand, three hundred thirty-one".