Base | Representation |
---|---|
bin | 10101000111111110… |
… | …11010011011010001 |
3 | 1002021101112220011021 |
4 | 22203333122123101 |
5 | 141211324302423 |
6 | 5113214115441 |
7 | 551021661433 |
oct | 124377323321 |
9 | 32241486137 |
10 | 11341244113 |
11 | 489a922621 |
12 | 22461abb81 |
13 | 10b9836344 |
14 | 79833c653 |
15 | 4659e895d |
hex | 2a3fda6d1 |
11341244113 has 2 divisors, whose sum is σ = 11341244114. Its totient is φ = 11341244112.
The previous prime is 11341244111. The next prime is 11341244141. The reversal of 11341244113 is 31144214311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7175445264 + 4165798849 = 84708^2 + 64543^2 .
It is a cyclic number.
It is not a de Polignac number, because 11341244113 - 21 = 11341244111 is a prime.
Together with 11341244111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11341244111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670622056 + 5670622057.
It is an arithmetic number, because the mean of its divisors is an integer number (5670622057).
Almost surely, 211341244113 is an apocalyptic number.
It is an amenable number.
11341244113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341244113 is an equidigital number, since it uses as much as digits as its factorization.
11341244113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1152, while the sum is 25.
Adding to 11341244113 its reverse (31144214311), we get a palindrome (42485458424).
The spelling of 11341244113 in words is "eleven billion, three hundred forty-one million, two hundred forty-four thousand, one hundred thirteen".
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