Base | Representation |
---|---|
bin | 10000100000001111000… |
… | …101010111101100001101 |
3 | 11000102101002012112100211 |
4 | 100200033011113230031 |
5 | 122040141323312031 |
6 | 2225002022322421 |
7 | 144636442420621 |
oct | 20401705275415 |
9 | 4012332175324 |
10 | 1134124432141 |
11 | 3a7a85747a28 |
12 | 163973b89411 |
13 | 82c417ab15c |
14 | 3cc6b5b7181 |
15 | 1e77b72dbb1 |
hex | 1080f157b0d |
1134124432141 has 2 divisors, whose sum is σ = 1134124432142. Its totient is φ = 1134124432140.
The previous prime is 1134124432117. The next prime is 1134124432157. The reversal of 1134124432141 is 1412344214311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1066167762916 + 67956669225 = 1032554^2 + 260685^2 .
It is a cyclic number.
It is not a de Polignac number, because 1134124432141 - 211 = 1134124430093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1134124439141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567062216070 + 567062216071.
It is an arithmetic number, because the mean of its divisors is an integer number (567062216071).
Almost surely, 21134124432141 is an apocalyptic number.
It is an amenable number.
1134124432141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134124432141 is an equidigital number, since it uses as much as digits as its factorization.
1134124432141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9216, while the sum is 31.
Adding to 1134124432141 its reverse (1412344214311), we get a palindrome (2546468646452).
The spelling of 1134124432141 in words is "one trillion, one hundred thirty-four billion, one hundred twenty-four million, four hundred thirty-two thousand, one hundred forty-one".
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