Base | Representation |
---|---|
bin | 10101000111111111… |
… | …01111111011101011 |
3 | 1002021101201100222212 |
4 | 22203333233323223 |
5 | 141211340112303 |
6 | 5113220035335 |
7 | 551022506315 |
oct | 124377577353 |
9 | 32241640885 |
10 | 11341332203 |
11 | 489a982823 |
12 | 2246232b4b |
13 | 10b9867476 |
14 | 7983627b5 |
15 | 465a14ad8 |
hex | 2a3fefeeb |
11341332203 has 4 divisors (see below), whose sum is σ = 11341884120. Its totient is φ = 11340780288.
The previous prime is 11341332157. The next prime is 11341332217. The reversal of 11341332203 is 30223314311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11341332203 - 210 = 11341331179 is a prime.
It is a super-2 number, since 2×113413322032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11341332263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243893 + ... + 286646.
It is an arithmetic number, because the mean of its divisors is an integer number (2835471030).
Almost surely, 211341332203 is an apocalyptic number.
11341332203 is a deficient number, since it is larger than the sum of its proper divisors (551917).
11341332203 is an equidigital number, since it uses as much as digits as its factorization.
11341332203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 551916.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11341332203 its reverse (30223314311), we get a palindrome (41564646514).
The spelling of 11341332203 in words is "eleven billion, three hundred forty-one million, three hundred thirty-two thousand, two hundred three".
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