Base | Representation |
---|---|
bin | 10101000111111111… |
… | …10000000000000001 |
3 | 1002021101201101101011 |
4 | 22203333300000001 |
5 | 141211340114411 |
6 | 5113220040521 |
7 | 551022510163 |
oct | 124377600001 |
9 | 32241641334 |
10 | 11341332481 |
11 | 489a982a56 |
12 | 2246233141 |
13 | 10b986762b |
14 | 798362933 |
15 | 465a14c21 |
hex | 2a3ff0001 |
11341332481 has 2 divisors, whose sum is σ = 11341332482. Its totient is φ = 11341332480.
The previous prime is 11341332479. The next prime is 11341332523. The reversal of 11341332481 is 18423314311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11341185025 + 147456 = 106495^2 + 384^2 .
It is a cyclic number.
It is not a de Polignac number, because 11341332481 - 21 = 11341332479 is a prime.
It is a super-2 number, since 2×113413324812 (a number of 21 digits) contains 22 as substring.
Together with 11341332479, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11341332461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670666240 + 5670666241.
It is an arithmetic number, because the mean of its divisors is an integer number (5670666241).
Almost surely, 211341332481 is an apocalyptic number.
It is an amenable number.
11341332481 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341332481 is an equidigital number, since it uses as much as digits as its factorization.
11341332481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 31.
Adding to 11341332481 its reverse (18423314311), we get a palindrome (29764646792).
The spelling of 11341332481 in words is "eleven billion, three hundred forty-one million, three hundred thirty-two thousand, four hundred eighty-one".
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