Base | Representation |
---|---|
bin | 110100110011111110… |
… | …1111100001000000001 |
3 | 101211201222101200202211 |
4 | 1221213331330020001 |
5 | 3324232320040001 |
6 | 124033523342121 |
7 | 11123330222401 |
oct | 1514775741001 |
9 | 354658350684 |
10 | 113413440001 |
11 | 44109a26104 |
12 | 19b91b21941 |
13 | a90574a2a4 |
14 | 56bc68c801 |
15 | 2e3bb07351 |
hex | 1a67f7c201 |
113413440001 has 2 divisors, whose sum is σ = 113413440002. Its totient is φ = 113413440000.
The previous prime is 113413439963. The next prime is 113413440017. The reversal of 113413440001 is 100044314311.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 73592838400 + 39820601601 = 271280^2 + 199551^2 .
It is a cyclic number.
It is not a de Polignac number, because 113413440001 - 27 = 113413439873 is a prime.
It is not a weakly prime, because it can be changed into another prime (113413440071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56706720000 + 56706720001.
It is an arithmetic number, because the mean of its divisors is an integer number (56706720001).
Almost surely, 2113413440001 is an apocalyptic number.
It is an amenable number.
113413440001 is a deficient number, since it is larger than the sum of its proper divisors (1).
113413440001 is an equidigital number, since it uses as much as digits as its factorization.
113413440001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 113413440001 its reverse (100044314311), we get a palindrome (213457754312).
The spelling of 113413440001 in words is "one hundred thirteen billion, four hundred thirteen million, four hundred forty thousand, one".
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