Base | Representation |
---|---|
bin | 110100110011111110… |
… | …1111100110110111111 |
3 | 101211201222101211220011 |
4 | 1221213331330312333 |
5 | 3324232320134012 |
6 | 124033523404051 |
7 | 11123330234224 |
oct | 1514775746677 |
9 | 354658354804 |
10 | 113413443007 |
11 | 44109a28397 |
12 | 19b91b23627 |
13 | a90574b777 |
14 | 56bc68d94b |
15 | 2e3bb081a7 |
hex | 1a67f7cdbf |
113413443007 has 2 divisors, whose sum is σ = 113413443008. Its totient is φ = 113413443006.
The previous prime is 113413442927. The next prime is 113413443023. The reversal of 113413443007 is 700344314311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113413443007 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 113413443007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113413443097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56706721503 + 56706721504.
It is an arithmetic number, because the mean of its divisors is an integer number (56706721504).
Almost surely, 2113413443007 is an apocalyptic number.
113413443007 is a deficient number, since it is larger than the sum of its proper divisors (1).
113413443007 is an equidigital number, since it uses as much as digits as its factorization.
113413443007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 113413443007 its reverse (700344314311), we get a palindrome (813757757318).
The spelling of 113413443007 in words is "one hundred thirteen billion, four hundred thirteen million, four hundred forty-three thousand, seven".
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