1134140141113 has 4 divisors (see below), whose sum is σ = 1296160161280. Its totient is φ = 972120120948.

The previous prime is 1134140141059. The next prime is 1134140141159. The reversal of 1134140141113 is 3111410414311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1134140141113 - 2¹³ = 1134140132921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1134140141713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81010010073 + ... + 81010010086.

It is an arithmetic number, because the mean of its divisors is an integer number (324040040320).

Almost surely, 2^{1134140141113} is an apocalyptic number.

It is an amenable number.

1134140141113 is a deficient number, since it is larger than the sum of its proper divisors (162020020167).

1134140141113 is an equidigital number, since it uses as much as digits as its factorization.

1134140141113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162020020166.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 1134140141113 its reverse (3111410414311), we get a palindrome (4245550555424).

The spelling of 1134140141113 in words is "one trillion, one hundred thirty-four billion, one hundred forty million, one hundred forty-one thousand, one hundred thirteen".