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113414244121463 is a prime number
BaseRepresentation
bin11001110010011001001111…
…101110111011101101110111
3112212120021222200012202211012
4121302121033232323231313
5104331134332443341323
61041113441240302435
732613623460642605
oct3162311756735567
9485507880182735
10113414244121463
113315679011557a
1210878534a71a1b
134b38bc04b331c
1420013c8a9c875
15d1a271105678
hex67264fbbbb77

113414244121463 has 2 divisors, whose sum is σ = 113414244121464. Its totient is φ = 113414244121462.

The previous prime is 113414244121441. The next prime is 113414244121499. The reversal of 113414244121463 is 364121442414311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113414244121463 - 214 = 113414244105079 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113414244121463.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113414244121063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56707122060731 + 56707122060732.

It is an arithmetic number, because the mean of its divisors is an integer number (56707122060732).

Almost surely, 2113414244121463 is an apocalyptic number.

113414244121463 is a deficient number, since it is larger than the sum of its proper divisors (1).

113414244121463 is an equidigital number, since it uses as much as digits as its factorization.

113414244121463 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 221184, while the sum is 41.

Adding to 113414244121463 its reverse (364121442414311), we get a palindrome (477535686535774).

The spelling of 113414244121463 in words is "one hundred thirteen trillion, four hundred fourteen billion, two hundred forty-four million, one hundred twenty-one thousand, four hundred sixty-three".