Base | Representation |
---|---|
bin | 10101001000000001… |
… | …00011101010110101 |
3 | 1002021102010010200112 |
4 | 22210000203222311 |
5 | 141211413402432 |
6 | 5113224352405 |
7 | 551024351201 |
oct | 124400435265 |
9 | 32242103615 |
10 | 11341544117 |
11 | 48a0007a62 |
12 | 2246315705 |
13 | 10b990ca67 |
14 | 7983b9b01 |
15 | 465a577b2 |
hex | 2a4023ab5 |
11341544117 has 2 divisors, whose sum is σ = 11341544118. Its totient is φ = 11341544116.
The previous prime is 11341544051. The next prime is 11341544129. The reversal of 11341544117 is 71144514311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7652925361 + 3688618756 = 87481^2 + 60734^2 .
It is a cyclic number.
It is not a de Polignac number, because 11341544117 - 216 = 11341478581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11341541117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670772058 + 5670772059.
It is an arithmetic number, because the mean of its divisors is an integer number (5670772059).
Almost surely, 211341544117 is an apocalyptic number.
It is an amenable number.
11341544117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341544117 is an equidigital number, since it uses as much as digits as its factorization.
11341544117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6720, while the sum is 32.
The spelling of 11341544117 in words is "eleven billion, three hundred forty-one million, five hundred forty-four thousand, one hundred seventeen".
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