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1134166062133 = 13831059799191
BaseRepresentation
bin10000100000010001100…
…100001011010000110101
311000102110222112112222101
4100200101210023100311
5122040233002442013
62225010110502101
7144640456315066
oct20402144132065
94012428475871
101134166062133
113a7aa71a1185
12163985b04931
1382c4a2c58a0
143cc72d3256d
151e7802038dd
hex1081190b435

1134166062133 has 16 divisors (see below), whose sum is σ = 1236254495616. Its totient is φ = 1034200964160.

The previous prime is 1134166062097. The next prime is 1134166062143. The reversal of 1134166062133 is 3312606614311.

It is not a de Polignac number, because 1134166062133 - 225 = 1134132507701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1134166062092 and 1134166062101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1134166062143) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11384568 + ... + 11483758.

It is an arithmetic number, because the mean of its divisors is an integer number (77265905976).

Almost surely, 21134166062133 is an apocalyptic number.

1134166062133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1134166062133 is a deficient number, since it is larger than the sum of its proper divisors (102088433483).

1134166062133 is a wasteful number, since it uses less digits than its factorization.

1134166062133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109884.

The product of its (nonzero) digits is 46656, while the sum is 37.

The spelling of 1134166062133 in words is "one trillion, one hundred thirty-four billion, one hundred sixty-six million, sixty-two thousand, one hundred thirty-three".

Divisors: 1 13 83 1079 10597 99191 137761 879551 1289483 8232853 11434163 107027089 1051127027 13664651351 87243543241 1134166062133