Base | Representation |
---|---|
bin | 10000100000010001100… |
… | …100001011010000110101 |
3 | 11000102110222112112222101 |
4 | 100200101210023100311 |
5 | 122040233002442013 |
6 | 2225010110502101 |
7 | 144640456315066 |
oct | 20402144132065 |
9 | 4012428475871 |
10 | 1134166062133 |
11 | 3a7aa71a1185 |
12 | 163985b04931 |
13 | 82c4a2c58a0 |
14 | 3cc72d3256d |
15 | 1e7802038dd |
hex | 1081190b435 |
1134166062133 has 16 divisors (see below), whose sum is σ = 1236254495616. Its totient is φ = 1034200964160.
The previous prime is 1134166062097. The next prime is 1134166062143. The reversal of 1134166062133 is 3312606614311.
It is not a de Polignac number, because 1134166062133 - 225 = 1134132507701 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1134166062092 and 1134166062101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1134166062143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11384568 + ... + 11483758.
It is an arithmetic number, because the mean of its divisors is an integer number (77265905976).
Almost surely, 21134166062133 is an apocalyptic number.
1134166062133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1134166062133 is a deficient number, since it is larger than the sum of its proper divisors (102088433483).
1134166062133 is a wasteful number, since it uses less digits than its factorization.
1134166062133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109884.
The product of its (nonzero) digits is 46656, while the sum is 37.
The spelling of 1134166062133 in words is "one trillion, one hundred thirty-four billion, one hundred sixty-six million, sixty-two thousand, one hundred thirty-three".
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