Base | Representation |
---|---|
bin | 10000100000010011100… |
… | …111010101010101001011 |
3 | 11000102120101020100100120 |
4 | 100200103213111111023 |
5 | 122040320303203420 |
6 | 2225013335434323 |
7 | 144641354464335 |
oct | 20402347252513 |
9 | 4012511210316 |
10 | 1134200444235 |
11 | 3a8014644a41 |
12 | 1639955259a3 |
13 | 82c54473321 |
14 | 3cc77722455 |
15 | 1e783245d40 |
hex | 108139d554b |
1134200444235 has 8 divisors (see below), whose sum is σ = 1814720710800. Its totient is φ = 604906903584.
The previous prime is 1134200444227. The next prime is 1134200444261. The reversal of 1134200444235 is 5324440024311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1134200444235 - 23 = 1134200444227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1134200444196 and 1134200444205.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37806681460 + ... + 37806681489.
It is an arithmetic number, because the mean of its divisors is an integer number (226840088850).
Almost surely, 21134200444235 is an apocalyptic number.
1134200444235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1134200444235 is a deficient number, since it is larger than the sum of its proper divisors (680520266565).
1134200444235 is an equidigital number, since it uses as much as digits as its factorization.
1134200444235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75613362957.
The product of its (nonzero) digits is 46080, while the sum is 33.
Adding to 1134200444235 its reverse (5324440024311), we get a palindrome (6458640468546).
The spelling of 1134200444235 in words is "one trillion, one hundred thirty-four billion, two hundred million, four hundred forty-four thousand, two hundred thirty-five".
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