Base | Representation |
---|---|
bin | 10101001000000111… |
… | …10111101100001001 |
3 | 1002021110202020221211 |
4 | 22210003313230021 |
5 | 141212124200203 |
6 | 5113255133121 |
7 | 551034626113 |
oct | 124403675411 |
9 | 32243666854 |
10 | 11342412553 |
11 | 48a055047a |
12 | 22466741a1 |
13 | 10b9b55124 |
14 | 7985643b3 |
15 | 465b79c6d |
hex | 2a40f7b09 |
11342412553 has 2 divisors, whose sum is σ = 11342412554. Its totient is φ = 11342412552.
The previous prime is 11342412551. The next prime is 11342412611. The reversal of 11342412553 is 35521424311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6096017929 + 5246394624 = 78077^2 + 72432^2 .
It is a cyclic number.
It is not a de Polignac number, because 11342412553 - 21 = 11342412551 is a prime.
Together with 11342412551, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11342412551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671206276 + 5671206277.
It is an arithmetic number, because the mean of its divisors is an integer number (5671206277).
Almost surely, 211342412553 is an apocalyptic number.
It is an amenable number.
11342412553 is a deficient number, since it is larger than the sum of its proper divisors (1).
11342412553 is an equidigital number, since it uses as much as digits as its factorization.
11342412553 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14400, while the sum is 31.
Adding to 11342412553 its reverse (35521424311), we get a palindrome (46863836864).
The spelling of 11342412553 in words is "eleven billion, three hundred forty-two million, four hundred twelve thousand, five hundred fifty-three".
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