Base | Representation |
---|---|
bin | 10000100000010110000… |
… | …101110111100111011001 |
3 | 11000102200021102202211112 |
4 | 100200112011313213121 |
5 | 122040411423102132 |
6 | 2225021422310105 |
7 | 144642400645205 |
oct | 20402605674731 |
9 | 4012607382745 |
10 | 1134242003417 |
11 | 3a803604aa76 |
12 | 1639a7428335 |
13 | 82c5cc64763 |
14 | 3cc7d05db05 |
15 | 1e786c04ab2 |
hex | 108161779d9 |
1134242003417 has 2 divisors, whose sum is σ = 1134242003418. Its totient is φ = 1134242003416.
The previous prime is 1134242003381. The next prime is 1134242003429. The reversal of 1134242003417 is 7143002424311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 568841774656 + 565400228761 = 754216^2 + 751931^2 .
It is a cyclic number.
It is not a de Polignac number, because 1134242003417 - 210 = 1134242002393 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134242003717) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567121001708 + 567121001709.
It is an arithmetic number, because the mean of its divisors is an integer number (567121001709).
Almost surely, 21134242003417 is an apocalyptic number.
It is an amenable number.
1134242003417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134242003417 is an equidigital number, since it uses as much as digits as its factorization.
1134242003417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 1134242003417 its reverse (7143002424311), we get a palindrome (8277244427728).
The spelling of 1134242003417 in words is "one trillion, one hundred thirty-four billion, two hundred forty-two million, three thousand, four hundred seventeen".
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