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11343000013 is a prime number
BaseRepresentation
bin10101001000001100…
…00111000111001101
31002021111212002210121
422210012013013031
5141212302000023
65113315504541
7551042623612
oct124406070715
932244762717
1011343000013
1148a0911884
1222468b8151
1310b9ccc637
14798678509
15465c43d5d
hex2a41871cd

11343000013 has 2 divisors, whose sum is σ = 11343000014. Its totient is φ = 11343000012.

The previous prime is 11343000007. The next prime is 11343000043. The reversal of 11343000013 is 31000034311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8217966409 + 3125033604 = 90653^2 + 55902^2 .

It is an emirp because it is prime and its reverse (31000034311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11343000013 - 217 = 11342868941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11343000043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671500006 + 5671500007.

It is an arithmetic number, because the mean of its divisors is an integer number (5671500007).

Almost surely, 211343000013 is an apocalyptic number.

It is an amenable number.

11343000013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11343000013 is an equidigital number, since it uses as much as digits as its factorization.

11343000013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 11343000013 its reverse (31000034311), we get a palindrome (42343034324).

The spelling of 11343000013 in words is "eleven billion, three hundred forty-three million, thirteen", and thus it is an aban number.