113430122437 has 2 divisors, whose sum is σ = 113430122438. Its totient is φ = 113430122436.

The previous prime is 113430122387. The next prime is 113430122441. The reversal of 113430122437 is 734221034311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102703584676 + 10726537761 = 320474^2 + 103569^2 .

It is an emirp because it is prime and its reverse (734221034311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113430122437 - 2¹¹ = 113430120389 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113430122399 and 113430122408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113430122537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56715061218 + 56715061219.

It is an arithmetic number, because the mean of its divisors is an integer number (56715061219).

Almost surely, 2^113430122437 is an apocalyptic number.

It is an amenable number.

113430122437 is a deficient number, since it is larger than the sum of its proper divisors (1).

113430122437 is an equidigital number, since it uses as much as digits as its factorization.

113430122437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 113430122437 its reverse (734221034311), we get a palindrome (847651156748).

The spelling of 113430122437 in words is "one hundred thirteen billion, four hundred thirty million, one hundred twenty-two thousand, four hundred thirty-seven".