Base | Representation |
---|---|
bin | 10101001000001100… |
… | …01100011110110001 |
3 | 1002021111220012221222 |
4 | 22210012030132301 |
5 | 141212303201001 |
6 | 5113320154425 |
7 | 551043044663 |
oct | 124406143661 |
9 | 32244805858 |
10 | 11343022001 |
11 | 48a0927353 |
12 | 2246908a15 |
13 | 10ba00964c |
14 | 798682533 |
15 | 465c4a61b |
hex | 2a418c7b1 |
11343022001 has 4 divisors (see below), whose sum is σ = 11418141504. Its totient is φ = 11267902500.
The previous prime is 11343021967. The next prime is 11343022051. The reversal of 11343022001 is 10022034311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10022034311 = 53 ⋅189094987.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11343022001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11343022051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37559525 + ... + 37559826.
It is an arithmetic number, because the mean of its divisors is an integer number (2854535376).
Almost surely, 211343022001 is an apocalyptic number.
It is an amenable number.
11343022001 is a deficient number, since it is larger than the sum of its proper divisors (75119503).
11343022001 is an equidigital number, since it uses as much as digits as its factorization.
11343022001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75119502.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 11343022001 its reverse (10022034311), we get a palindrome (21365056312).
The spelling of 11343022001 in words is "eleven billion, three hundred forty-three million, twenty-two thousand, one".
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