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11343022001 = 15175119351
BaseRepresentation
bin10101001000001100…
…01100011110110001
31002021111220012221222
422210012030132301
5141212303201001
65113320154425
7551043044663
oct124406143661
932244805858
1011343022001
1148a0927353
122246908a15
1310ba00964c
14798682533
15465c4a61b
hex2a418c7b1

11343022001 has 4 divisors (see below), whose sum is σ = 11418141504. Its totient is φ = 11267902500.

The previous prime is 11343021967. The next prime is 11343022051. The reversal of 11343022001 is 10022034311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10022034311 = 53189094987.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11343022001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11343022051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37559525 + ... + 37559826.

It is an arithmetic number, because the mean of its divisors is an integer number (2854535376).

Almost surely, 211343022001 is an apocalyptic number.

It is an amenable number.

11343022001 is a deficient number, since it is larger than the sum of its proper divisors (75119503).

11343022001 is an equidigital number, since it uses as much as digits as its factorization.

11343022001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75119502.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11343022001 its reverse (10022034311), we get a palindrome (21365056312).

The spelling of 11343022001 in words is "eleven billion, three hundred forty-three million, twenty-two thousand, one".

Divisors: 1 151 75119351 11343022001