Base | Representation |
---|---|
bin | 10000100000011010001… |
… | …010111011110101101111 |
3 | 11000102212001012201121000 |
4 | 100200122022323311233 |
5 | 122041031433042203 |
6 | 2225032305211343 |
7 | 144644161441515 |
oct | 20403212736557 |
9 | 4012761181530 |
10 | 1134310440303 |
11 | 3a8070743687 |
12 | 163a06330b53 |
13 | 82c711a6961 |
14 | 3cc881964b5 |
15 | 1e78cc224a3 |
hex | 1081a2bbd6f |
1134310440303 has 64 divisors (see below), whose sum is σ = 1717072560000. Its totient is φ = 739946161152.
The previous prime is 1134310440247. The next prime is 1134310440311. The reversal of 1134310440303 is 3030440134311.
1134310440303 is a `hidden beast` number, since 1 + 1 + 3 + 4 + 310 + 4 + 40 + 303 = 666.
It is not a de Polignac number, because 1134310440303 - 28 = 1134310440047 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1134310440353) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 99173301 + ... + 99184737.
It is an arithmetic number, because the mean of its divisors is an integer number (26829258750).
Almost surely, 21134310440303 is an apocalyptic number.
1134310440303 is a deficient number, since it is larger than the sum of its proper divisors (582762119697).
1134310440303 is a wasteful number, since it uses less digits than its factorization.
1134310440303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11961 (or 11955 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 1134310440303 its reverse (3030440134311), we get a palindrome (4164750574614).
The spelling of 1134310440303 in words is "one trillion, one hundred thirty-four billion, three hundred ten million, four hundred forty thousand, three hundred three".
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