113431130122 has 4 divisors (see below), whose sum is σ = 170146695186. Its totient is φ = 56715565060.

The previous prime is 113431130119. The next prime is 113431130161. The reversal of 113431130122 is 221031134311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 221031134311 = 13 ⋅17002394947.

It can be written as a sum of positive squares in only one way, i.e., 112628031201 + 803098921 = 335601^2 + 28339^2 .

It is a junction number, because it is equal to n+sod(n) for n = 113431130093 and 113431130102.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28357782529 + ... + 28357782532.

Almost surely, 2^113431130122 is an apocalyptic number.

113431130122 is a deficient number, since it is larger than the sum of its proper divisors (56715565064).

113431130122 is an equidigital number, since it uses as much as digits as its factorization.

113431130122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56715565063.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 113431130122 its reverse (221031134311), we get a palindrome (334462264433).

The spelling of 113431130122 in words is "one hundred thirteen billion, four hundred thirty-one million, one hundred thirty thousand, one hundred twenty-two".