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113432011103 = 993111422013
BaseRepresentation
bin110100110100100010…
…0110010000101011111
3101211210021100012112102
41221221010302011133
53324302043323403
6124035425355315
711123644120505
oct1515104620537
9354707305472
10113432011103
114411945a924
1219b98198b3b
13a9095501c8
1456c0d24675
152e3d574b88
hex1a6913215f

113432011103 has 4 divisors (see below), whose sum is σ = 113443443048. Its totient is φ = 113420579160.

The previous prime is 113432011067. The next prime is 113432011109. The reversal of 113432011103 is 301110234311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113432011103 - 210 = 113432010079 is a prime.

It is a super-2 number, since 2×1134320111032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113432011109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5701076 + ... + 5720937.

It is an arithmetic number, because the mean of its divisors is an integer number (28360860762).

Almost surely, 2113432011103 is an apocalyptic number.

113432011103 is a deficient number, since it is larger than the sum of its proper divisors (11431945).

113432011103 is an equidigital number, since it uses as much as digits as its factorization.

113432011103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11431944.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 113432011103 its reverse (301110234311), we get a palindrome (414542245414).

The spelling of 113432011103 in words is "one hundred thirteen billion, four hundred thirty-two million, eleven thousand, one hundred three".

Divisors: 1 9931 11422013 113432011103